MATH SOLVE

2 months ago

Q:
# PLEASE HELP GIVING THE BRAINLIEST!!!!!Which option bests describes the relationship: h(x) =1/2x2? Quadratic variation Direct linear variation Inverse variationExplain how you got your answer to question #2 using 1-2 complete sentencesWhich option bests describes the relationship: xy = 12? Direct linear variation Quadratic variation Inverse variationExplain how you got your answer to question #4 using 1-2 complete sentences.The length, g, of a cello string varies inversely as the frequency, f, of its vibrations (cycles per second). Suppose it is known that an 18-inch-long cello string vibrates 300 cycles per second.write an inverse variation equation for the situation above.Then, show how to find the frequency of a 15-inch-long cello string.

Accepted Solution

A:

Answer:quadratic variation inverse variationfrequency = 360 Step-by-step explanation:[tex]h(x)=\frac{1}{2}x^2[/tex]Here in h(x), we have x^2. x^2 always represents quadraticx^2 at the top. so its is a quadratic variation[tex]xy = 12[/tex]Divide both sides by xso [tex]y=\frac{12}{x}[/tex]y is inversely proportional to xso its inverse variationlength varies inversely as frequency, the equation is [tex]g=\frac{k}{f}[/tex]18-inch-long cello string vibrates 300 cycles per second.g=18 and f=300, solve for k[tex]g=\frac{k}{f}[/tex][tex]18=\frac{k}{300}[/tex]5400=k[tex]g=\frac{5400}{f}[/tex]length g= 15[tex]15=\frac{5400}{f}[/tex]multiply by f on both sides and divide both sides by 15f=360frequency = 360